dua garis 4x+py-7=0 dan x-2y-3=0 akan tegak lurus jika p=....
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Jawaban:
syarat Tegak Lurus m1xm2 = -1
4x+py -7 =0
py = -4x +7
x -2y -3 =0
-2y = -x +3
y = 1/2x -3/2
y = 1/2
m2 = 1/2
m1 × m2 = -1
py × 1/2 = -1
py = -1/1/2
py = -1 ×2/1
py = -2
p = -2
jika p =2 maka akan tegak lurus
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